Question
Given two angles are supplementary and one angle is $20^\circ$ more than other. Find the two angles
✓
Answer
Let the angles be $x$ and $x+20^{\circ}$ According to the problem,
$ x+x+20^{\circ}=180^{\circ}$
$2 x+20^{\circ}=180^{\circ}$
$2 x=180^{\circ}-20^{\circ}$
$2 x=160^{\circ}$
$x=\frac{160^{\circ}}{2}$
$x=80^{\circ}$
$x+20^{\circ}=80^{\circ}+20^{\circ}$
$=100^{\circ} $
$\therefore$ The two angles are $80^{\circ}$ and $100^{\circ}$
$ x+x+20^{\circ}=180^{\circ}$
$2 x+20^{\circ}=180^{\circ}$
$2 x=180^{\circ}-20^{\circ}$
$2 x=160^{\circ}$
$x=\frac{160^{\circ}}{2}$
$x=80^{\circ}$
$x+20^{\circ}=80^{\circ}+20^{\circ}$
$=100^{\circ} $
$\therefore$ The two angles are $80^{\circ}$ and $100^{\circ}$
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