MCQ
Greatest value of the function, $f(x) = - 1 + \frac{2}{{{2^x}^2 + 1}}$ is
- A$1$
- B$3/2$
- C$2/3$
- ✓$0$
Clearly $f(x)$ in an even function and $f(x)$ is greatest
when $\frac{2}{2^{x^{2}}+1}$ is greatest.
(given)
Also, $\frac{2}{2^{x^{2}}+1}$ is greatest when $2^{x^{2}}+1$ is least,
which occurs when $x=0.$
Hence greatest value is $f(0)=0.$
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$\mathrm{f}(\mathrm{x})=\log _{\sqrt{5}}(3+\cos \left(\frac{3 \pi}{4}+\mathrm{x}\right)+\cos \left(\frac{\pi}{4}+\mathrm{x}\right)+\cos \left(\frac{\pi}{4}-\mathrm{x}\right)$
$-\cos \left(\frac{3 \pi}{4}-\mathrm{x}\right))$ is :