MCQ
Greatest value of the function, $f(x) = - 1 + \frac{2}{{{2^x}^2 + 1}}$ is
- A$1$
- B$3/2$
- C$2/3$
- ✓$0$
Clearly $f(x)$ in an even function and $f(x)$ is greatest
when $\frac{2}{2^{x^{2}}+1}$ is greatest.
(given)
Also, $\frac{2}{2^{x^{2}}+1}$ is greatest when $2^{x^{2}}+1$ is least,
which occurs when $x=0.$
Hence greatest value is $f(0)=0.$
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$\left(x^2+4\right)^2 d y+\left(2 x^3 y+8 x y-2\right) d x=0 \text {. If } y(0)=0 \text {, }$ then $y(2)$ is equal to