Question
$H _2 S$ is less acidic than $H _2 Te$, why?

Answer

Sulphur is more electronegative than Tellurium.
Bond energy of $S-H$ in $H _2 S$ is $\left(347 \ kJ \ mol ^{-1}\right)$ more than the bond energy of $Te-H$
$\left(238 \ kJ \ mol ^{-1}\right)$.
Hence $H _2 Te$. dissociates more giving $ H + \left(\right.$ or $\left.H _3 O ^{+}\right)$ than $H _2 S$ in the solution. Therefore $H _2 S$ is less acidic than $H _2 Te$.

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