MCQ
${H_2}{O_2}$ on reaction with $PbS$ gives
- A$PbO$
- ✓$PbS{O_4}$
- C$Pb{O_2}$
- D$PbHS{O_4}$
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$M(s) \to M(g)\,\,\,\,\,\,\,\,\,\,\,\,\,\, ........(1)$
$M(s) \to M^{2+} (g) + 2e^-\,\,\,\,\,\,\,\,.......(2)$
$M(g) \to M^+(g) + e^-\,\,\,\,\,\,\,\,\,\,\,.........(3)$
$M^+ (g) \to M^{2+} (g) + e^-\,\,\,\,\,\,\,\,\,.........(4)$
$M(g) \to M^{2+} (g) +2e^-\,\,\,\,\,\,\,\,\,\,\,..........(5)$
The second ionization energy of $M$ could be calculated from the energy values assoclated with
$(i)\,\,$on doubling the initial concentration of $A$ only, the rate of reaction is also doubled and
$(ii)$ on doubling the initial concentration of both $A$ and $B,$ there is a change by a factor of $8$ in the rate of the reaction.
The rate of this reaction is given by