MCQ
${H_2}S$ acts only as a reducing agent while $S{O_2}$ can act both as a reducing and oxidizing agent because
- A$S$ in ${H_2}S$ has $-2$ oxidation state
- B$S$ in $S{O_2}$ has oxidation state $+ 4$
- CHydrogen in ${H_2}S$ more $+ve$ than oxygen
- ✓Both $(a)$ and $(b)$
