MCQ
${H_2}S$ acts only as a reducing agent while $S{O_2}$ can act both as a reducing and oxidizing agent because
  • A
    $S$ in ${H_2}S$ has $-2$  oxidation state
  • B
    $S$ in $S{O_2}$ has oxidation state $+ 4$
  • C
    Hydrogen in ${H_2}S$ more $+ve$ than oxygen
  • Both $(a)$ and $(b)$

Answer

Correct option: D.
Both $(a)$ and $(b)$
(d) In ${H_2}S$ sulphur shows $-2$ oxidation state and in $S{O_2}$ shows $+4$ oxidation state. Hence $S{O_2}$ shows both oxidising and reducing properties.

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