MCQ
${H_2}S$ is more acidic than ${H_2}O$, due to
- A$O$ is more electronegative than $S$
- ✓$O - H$ bond is stronger than $S - H$ bond
- C$O - H$ bond is weaker than $S - H$ bond
- DNone of these
✓
Answer
Correct option: B.
$O - H$ bond is stronger than $S - H$ bond
b
(b)The acidity of hydrides of $VI$ group elements increase from top to bottom as the bond strength $X - H$ decrease from top to bottom
(b)The acidity of hydrides of $VI$ group elements increase from top to bottom as the bond strength $X - H$ decrease from top to bottom
${H_2}O < {H_2}S < {H_2}Se < {H_2}Te$
Need a full question paper?
Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.
Explore more
Similar questions
Identify major product $P_3$ :
→The $IUPAC$ name of $CH_2 = CH - CH = CH_2$ is
→In which case Raoult's law is not applicable
Methanides are
A colourless organic compound gives brisk effervescences with a mixture of sodium nitrite and dil. $HCl$. It could be
→Addition of a mineral acid to an olefin bond leads to major product, Identify it
Dilute aqueous $KMn{O_4}$, at room temperature reacts with ${\rm{ }}R - CH = CH - R$ to give
→The hybridisation in methane, ethene and Ethyne respectively is
The total number of anti bonding molecular orbitals, formed from $2 \mathrm{~s}$ and $2 \mathrm{p}$ atomic orbitals in a diatomic molecule is_______
→The number of optical isomers for the given compound
→$\begin{array}{*{20}{c}}
{C{H_3} - CH - CH - C{H_2} - COOH} \\
{|\,\,\,\,\,\,\,\,\,\,\,\,\,|\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,} \\
{\,\,OH\,\,\,\,\,\,\,\,Cl\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,}
\end{array}$