MCQ
${H_2}S$ reacts with halogens, the halogens
- AForm sulphur halides
- BAre oxidised
- ✓Are reduced
- DNone of these
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$(i)$ $CH_3CH_2COCH_2Cl$ $(ii)$ $C_6H_5COCH_3$
$(iii)$ $C_6H_5COCHCl_2$ $(iv)$ $CH_3CH_2COCCl_3$
$\underset{(1)}{\mathop{C{{H}_{3}}C{{H}_{2}}CHO}}\,$
$\underset{(2)}{\mathop{\begin{matrix}
O \\
|| \\
C{{H}_{3}}-C-C{{H}_{3}} \\
\end{matrix}}}\,$
$\underset{(3)}{\mathop{C{{H}_{3}}-CH=CH-OH}}\,$

$Ca(OH)_2 + H_3PO_4\to CaHPO_4 + 2H_2O$ is
$CH_3 (CH_2)_8CH_2Br \xrightarrow[benzene]{KCN} CH_3 (CH_2)_8CH_2CN$