MCQ
$HBr$ reacts with $CH_2 = CH -OCH_3$ at room temperature to give
- A$BrCH_2CHO$ and $CH_3OH$
- B$BrCH_2-CH_2-OCH_3$
- ✓$H_3C-CHBr-OCH_3$
- D$CH_3CHO$ and $CH_3Br$
✓
Answer
Correct option: C.
$H_3C-CHBr-OCH_3$
c
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