MCQ
$HI$ cannot be prepared by the action of conc. ${H_2}S{O_4}$ on $KI$ because
- A$HI$ is stronger than ${H_2}S{O_4}$
- B$HI$ is more volatile than ${H_2}S{O_4}$
- ✓${H_2}S{O_4}$ is an oxidising agent
- D${H_2}S{O_4}$ forms complex
✓
Answer
Correct option: C.
${H_2}S{O_4}$ is an oxidising agent
c
(c) $KI + {H_2}S{O_4}\, \to \,KHS{O_4} + HI$
(c) $KI + {H_2}S{O_4}\, \to \,KHS{O_4} + HI$
$HI$ is formed but it is further oxidised by conc. ${H_2}S{O_4}$ into ${I_2}$
$2HI + {H_2}S{O_4}\, \to \,2{H_2}O + \mathop {{I_2} + S{O_2}}\limits_{{\rm{Violet vapour}}} \uparrow $
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