- ALa(OH)3 is less basic than Lu(OH)3.
- BIn Lanthanide series ionic radius of Ln+3 ions decreases.
- CLa is actually an element of transition series rather Lanthanide.
- DAomic radius of Zr and Hf are same because of Lanthanide contraction.
Explanation:
La(OH)3 is less basic than Lu(OH)3 is an incorrect statement.
Basic strength La(OH)3 > Lu(OH)3
Due to Lanthanide contraction as the size of the lanthanide ions decreases from La+3 to Lu+3, the covalent character of hydroxides increases and hence basic strength decreases.
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$(i)$ $\left[ FeF _{6}\right]^{3-}$
$(ii)$ $\left[ Co \left( NH _{3}\right)_{6}\right]^{3+}$
$(iii)$ $\left[ NiCl _{4}\right]^{2-}$
$(iv)$ $\left[ Cu \left( NH _{3}\right)_{4}\right]^{2+}$
Temperature $\quad$ Equilibrium constant
$\begin{array}{ll} T _{1}=25^{\circ} C & K _{1}=100 \\ T _{2}=100^{\circ} C & K _{2}=100\end{array}$
The values of $\Delta H ^{\circ}, \Delta G ^{\circ}$ at $T _{1}$ and $\Delta G ^{\circ}$ at $T _{2}$ (in $kJ\, mol ^{-1}$ ) respectively, are close to $\left[\right.$ Use $\left. R =8.314\, JK ^{-1} mol ^{-1}\right]$
$A$. The strength of anionic ligands can be explained by crystal field theory.
$B$. Valence bond theory does not give a quantitative interpretation of kinetic stability of coordination compounds.
$C$. The hybridization involved in formation of $\left[\mathrm{Ni}(\mathrm{CN})_4\right]^{2-}$ complex is $\mathrm{dsp}^2$.
$D$. The number of possible isomer$(s)$ of cis- $\left[\mathrm{PtCl}_2(\text { en })_2\right]^{2+}$ is one
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