- A$Ca{F_2}$
- B$CaC{l_2}$
- C$CaB{r_2}$
- ✓$Ca{I_2}$
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$\begin{array}{*{20}{c}}
{\,\,\,\,\,C{H_3}} \\
| \\
{C{H_3} - C - ONa} \\
| \\
{\,\,\,\,\,C{H_3}}
\end{array}\, + \,C{H_3}C{H_2}Cl\,\xrightarrow{{ - NaCl}}\,$ $\begin{array}{*{20}{c}}
{C{H_3}\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,} \\
{\,\,\,|\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,} \\
{C{H_3} - C - O - C{H_2} - C{H_3}} \\
{\,|\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,} \\
{C{H_3}\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,}
\end{array}$
is called
${N_2}{O_4}(g) \rightleftharpoons 2N{O_2}(g),\,\,\frac{{{K_c}}}{{{K_p}}}$ is
The rate determining step of the reaction is