- A$Ir$
- ✓$Os$
- C$Pb$
- D$Hg$
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Possible number of elimination products (alkene) of the given reaction is?
[Given $: R =8.31 \,J \,K ^{-1} \,mol ^{-1}, \log 1.33=0.1239$ $\ln 10=2.3]$
$(A)$ Number of lone pairs on oxygen is 2 .
$(B)$ $FOF$ angle is less than $104.5^{\circ}$.
$(C)$ Oxidation state of $O$ is $-2$.
$(D)$ Molecule is bent ' $V$ ' shaped.
$(E)$ Molecular geometry is linear.
Correct options are:
$N_{2(g)} + 3H_{2(g)} \rightarrow 2NH_{3(g)}$ The equality relationship between $\frac{d[NH_3]}{dt}$ and $\frac{d[H_2]}{dt}$ is
$Zn^{2+} + 2e^-$ $\longrightarrow$ $Zn (s) ; E^o = -0.76\,V$
$Ca^{2+} + 2e^-$ $\longrightarrow$ $Ca (s) ; E^o = -2.87\,V$
$Mg^{2+} + 2e^-$ $\longrightarrow$ $Mg (s) ; E^o = -2.36\,V$
$Ni^{2+} + 2e^-$ $\longrightarrow$ $Ni (s) ; E^o = -0.25\,V$
The reducing power of the metals increases in the order