Highest oxidation state of manganese in fluoride is $+4 (MnF_4)$ but highest oxidation state in oxides is $+7 (Mn_2O_7)$ because $............$
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The highest oxidation state of manganese in fluoride is $+4 (MnF_4)$ but in oxides it is $+7 (Mn_2O_7)$ because in covalent compounds fluorine can form single bond only while oxygen forms double bond.
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