MCQ
Highest $pH =14$ is given by
- A$0.1\,M\,{H_2}S{O_4}$
- B$0.1\,M\,NaOH$
- ✓$1\,N\,NaOH$
- D$1\,N\,HCl$
✓
Answer
Correct option: C.
$1\,N\,NaOH$
(c) $1\,N$ $NaOH$ solution have highest $pH$
$[O{H^ - }] = 1;\,\,pOH = 0$; $pH + pOH = 14$
$pH = 14 - 0 = 14$
Need a full question paper?
Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.
Explore more
Similar questions
The electronic configuration for Neodymium is: [Atomic Number for Neodymium $60$]
→Major product of above reaction is
Match List-I with List-$II$
→|
List-$I$ (Complexion) |
List-$II$ (Spin only magnetic moment in B.M.) |
| $A$ ${\left[\mathrm{Cr}\left(\mathrm{NH}_5\right)_0\right]^{3+}}$ | $I$ $4.90$ |
| $B$ ${\left[\mathrm{NiCl}_4\right]^{2-}}$ | $II$ $3.87$ |
| $C$ ${\left[\mathrm{CoF}_6\right]^{3-}}$ | $III$ $0.0$ |
| $D$ ${\left[\mathrm{Ni}(\mathrm{CN})_4\right]^{2-}}$ | $IV$ $2.83$ |
Choose the correct answer from the options given below:
Two benzyne intermediates are likely to be formed equally. Reaction with amide ion can occur in two different directions with each benzyne, giving three possible products. They are formed in a $1 : 2 : 1$ ratio. Asterisk $(^*)$ refers to $^{14}C.$
→product $(A)$ is
In hydrogen spectrum; If $n = 4$ then ratio of number of lines in emission spectrum, in the ultraviolet and visible regions isIn hydrogen spectrum; If $n = 4$ then ratio of number of lines in emission spectrum, in the ultraviolet and visible regions is
→What will be the $pH$ of an aqueous solution of $1.0\, M$ ammonium formate ? (Given: $pK_a = 3.8$ and $pK_b = 4.8$)
→The electron affinity of $Be$ is similar to :-
→Metallic sodium does not react normally with:
The $IUPAC$ name of neopentane is :-
→Given:
→$C{o^{3 + }}{e^ - } \longrightarrow C{o^{2 + }};\,{E^o} = 1.81\,V$
$P{b^4} + 2{e^ - } \longrightarrow P{b^{2 + }};\,{E^o} = + 1.67\,V$
$C{e^{4 + }} + {e^ - } \longrightarrow C{e^{3 + }};\,{E^o} = + 1.61\,V$
$B{i^{3 + }} + 3{e^ - } \longrightarrow Bi;\,{E^o} = + 0.20\,V$
Oxidizing power of the species will increase in the order