MCQ
Highest stable $Mn$ fluoride is $MnF_4$ where as highest $Mn$ oxide is $Mn_2O_7$ due to
- A$O$ atom is smaller the $F$.
- ✓Oxygen has ability to form multiple bonds
- C$Mn^{7+}$ does not exist
- D$F$ can not-stabilise higher oxidation states
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The product is
$BrO_{3(aq)}^ - \, + \,5Br_{(aq)}^ - \, + \,6{H^ - }\, \to \,3B{r_{2(l)}}\, + \,3{H_2}{o_{(l)}}.$
The rate of appearance of bromine $(Br_2)$ is related to rate of disappearance of bromide ions as
