MCQ
$HN{O_3}$ in aqueous solution yields
- A$NO_3^ - $ and ${H^ + }$
- ✓$NO_3^ - $ and ${H_3}{O^ + }$
- C$NO_2^ - $ and $O{H^ - }$
- D${N_2}{O_5}$ and ${H_2}O$
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$C{H_3} - CH = CH - CH\left( {OH} \right) - Me$ is
$(i)$ $Co^{3+}$ (Octahedral complex with a strong field ligand)
$(ii)$ $Co^{3+}$ (Octahedral complex with a weak field ligand like $F^-$ )
$(iii)$ $Co^{2+}$ (Tetrahedral complex)
$(iv)$ $Co^{2+}$ (Square planar complex)