MCQ
$HNO_3 + P_4O_{10} \to 4HPO_3 + X$ . $X$ is
- ✓$N_2O_5$
- B$NO_2$
- C$NO$
- D$N_2O_3$
$4 HNO _3+ P _4 O _{10} \rightarrow 4 HPO _3+2 N _2 O _5$
The product, $x$ is dinitrogen pentaoxide $\left( N _2 O _5\right)$.
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${C_6}{H_6}\left( \ell \right) + \frac{{15}}{2}{O_2} \to 6C{O_2}\left( g \right) + 3{H_2}O\left( \ell \right)\,\,\,\,\Delta H = - 3271\,kJ$
What is the value of $\Delta U$ for combustion of $1.5\, mol$ benzene at $27\,^oC$ ? .....$kJ$

| List $-I$ | List $-II$ |
| $(A)$ Benzaldehyde | $(i)$ Phenolphthalein |
| $(B)$ Phthalic anhydride | $(ii)$ Benzoincondensation |
| $(C)$ Phenyl benzoate | $(iii)$ Oil of wintergreen |
| $(D)$ Methyl salicylate | $(iv)$ Friesre arrangement |