MCQ
$HO - C{H_2} - C{H_2} - C{H_2} - C{H_2} - CH = C{H_2}\xrightarrow{{B{r_2}}}{\text{Product ?}}$
- ✓

- B

- C

- D






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$2MnO_4^ - + 5{C_2}O_4^{2 - } + 16{H^ + } \to 2M{n^{2 + }} + 10C{O_2} + 8{H_2}O$
Here $20\,ml$ of $0.1\,M$ $KMn{O_4}$ is equivalent to
