MCQ
Hofmann's hypobromite reaction affords a method of
- APreparing a tertiary amine
- BPreparing a mixture of amines
- ✓Stepping down a series
- DStepping up a series
✓
Answer
Correct option: C.
Stepping down a series
c
(c) $\mathop {C{H_3}CON{H_2}}\limits_{({\rm{2c}})} + B{r_2} + 4KOH \to $ $\mathop {C{H_3}N{H_2}}\limits_{{\rm{(1c)}}} + {K_2}C{O_3} + 3KBr + 2{H_2}O$
(c) $\mathop {C{H_3}CON{H_2}}\limits_{({\rm{2c}})} + B{r_2} + 4KOH \to $ $\mathop {C{H_3}N{H_2}}\limits_{{\rm{(1c)}}} + {K_2}C{O_3} + 3KBr + 2{H_2}O$
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