MCQ
Holme signal can be given by the using
- A$CaC_2 + CaCN_2$
- ✓$CaC_2 + Ca_3P_2$
- C$CaC_2 + CaCO_3$
- D$Ca_3P_2 + CaCN_2$
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(image) $\xrightarrow{{B{r_3} + C{H_3} - COOH}}A\xrightarrow{{Alc.KOH}}B$ (Product with six membered ring) $\xrightarrow[{(2)\,{H_2}O}]{{(1)\,C{H_3} - MgBr}}C\xrightarrow{{{H^ \oplus } + \Delta }}D\xrightarrow{{HBr(1\,mole)}}E$
Given $\left( E _{ Cu ^{2+} / Cu ^{+}}^{0}=0.16 V \right.$ $E _{ Cu ^{+} / Cu }^{0}=0.52 V$$\left.\frac{ RT }{ F }=0.025\right)$

$Zn_{(s)} +Cu^{+2}_{(aq)} \to Zn^{2+}_{(aq)} +Cu_{(s)}$
$[E^o_{Cu^{+2 /Cu}} = 0.34\,V$ , $E^o_{Zn^{2+} /Zn} = -0.76\,V ]$