MCQ
Homologue of $CH_3-Cl$ is
  • A
    $CH_3-CH_2-Br$
  • B
    $\begin{array}{*{20}{c}}
      {C{H_3} - CH - I} \\ 
      {\,|} \\ 
      {\,\,\,\,\,\,\,\,C{H_3}} 
    \end{array}$
  • $CH_3-CH_2-CH_2-Cl$
  • D
    $CH_3-(CH_2)_5-F$

Answer

Correct option: C.
$CH_3-CH_2-CH_2-Cl$
c

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