Question
How are $0.50 mol Na _2 CO _3$ and 0.50 M $Na _2 CO _3$ different?

Answer

molar mass of $Na _2 CO _3$
$
\begin{aligned}
=(2 \times 23)+12+(3 \times 16) & =106 g mol^{-1} \\
0.5 mol Na_2 CO_3 \text { means } 0.50 & \times 106 g^{-1} \\
= & 53 g Na_2 CO_3
\end{aligned}
$
and $0.50 M Na _2 CO _3$ means $53 g Na _2 CO _3$ is present in one liter solution.

Need a full question paper?

Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.

Start Generating Free