Question
How are $XeO_3$ and $XeOF_4$ prepared?

Answer

Preparation of $XeO_3$: It is prepared by the hydrolysis of $XeF_4$ and $XeF_6$ under controlled pH of medium.$6\text{XeF}_4+12\text{H}_2\text{O}\rightarrow4\text{Xe}^-+2\text{XeO}_3+24\text{HF}+3\text{O}_2$
$\text{XeF}_4+3\text{H}_2\text{O}\rightarrow\text{XeO}_3+6\text{HF}$
Preparation of $XeOF_4$ Partial hydrolysis of $XeF_6$ gives $XeOF_4.\text{XeF}_6+\text{H}_2\text{O}\rightarrow\text{XeO}_4+2\text{HF}$

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