How do you explain the presence of five —OH groups in glucose mol… - Vidyadip

Question

How do you explain the presence of five —OH groups in glucose molecule?

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Answer

Glucose gives penta-acetyl derivative on acetylation with acetic anhydride.
$\text{CHO}| (\text{CHOH})_4|\text{CH}_2\text{OH}|\text{CH}_2\text{OH}\xrightarrow{\ \ \ \ \ \ \ \ \ }\text{CHO}|(\text{CHOCOCH}_3)_4|\text{CH}_2\text{OH}_2\text{OCOCH}_3$
This confirms the presence of five -OH groups.

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