Question
How does $AlCl _3$ reacts with following reagents?
1. $H _2 O$
2. $NH _4 OH$
3. NaOH

Answer

1. When aluminium chloride reacts with water to form aluminium hydroxide.
$
AlCl _3+3 H _2 O \rightarrow Al ( OH )_3+3 HCl
$
2. With ammonium hydroxide, aluminium chloride forms aluminium hydroxide.
$
AlCl _3+3 NH _7 OH \rightarrow Al ( OH )_3+3 NH _4 C _1
$
3. With excess of sodium hydroxide $AlCl _3$ produces sodium meta aluminate.
$
AlCl _3+4 NaOH \rightarrow NaAlO _2+2 H _2 O +3 NaCl
$

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