Question
How does the resistance ( $R$ ) of a wire depend upon its radius ( $r$ )?

Answer

As $R \propto \frac{1}{A} \propto \frac{1}{\pi r^2} \quad\left(\because A=\pi r^2\right)$
$
\therefore R \propto \frac{1}{r^2} \quad(\because \pi=\text { constant })
$

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