Question
How many A.P.'s with 10 terms are there whose first term is in the set {1, 2, 3} and whose common difference is in the set {1, 2, 3, 4, 5}?

Answer

There are 3 ways to choose the first form and corresponding to each such way there are 5 ways of selecting the comm on difference. So, required number of A.P.'s = 3 × 5 = 15

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