Question
How many bricks will be required to construct a wall $8\ m$ long, $6\ m$ high and $22.5\ cm$ thick if each brick measures $(25\ cm \times 11.25\ cm \times 6\ cm)$?
✓
Answer
Volume of a cuboid $=$ Length $\times$ Breadth $\times$ height
$1\ m = 100$
Volume of wall $= 8\ m \times 6\ m \times 0.225\ m $
$= 10.8m^3$
Volume of a brick $= 0.25\ m \times 0.1125\ m \times 0.06\ m $
$= 0.0016875\ m^3$
No. of bricks $=\frac{\text{Volume of wall }}{\text{Volume of a brick }}$
$=\frac{10.8}{0.0016875}$
$=6400$
$1\ m = 100$
Volume of wall $= 8\ m \times 6\ m \times 0.225\ m $
$= 10.8m^3$
Volume of a brick $= 0.25\ m \times 0.1125\ m \times 0.06\ m $
$= 0.0016875\ m^3$
No. of bricks $=\frac{\text{Volume of wall }}{\text{Volume of a brick }}$
$=\frac{10.8}{0.0016875}$
$=6400$
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