MCQ
How many bricks will be required to construct a wall $8m$ long, $6m$ high and $22.5\ cm$ thick if each brick measures$ (25\ cm × 11.25 × 6\ cm)?$
- A$4800$
- B$5600$
- ✓$6400$
- D$5200$
✓
Answer
Correct option: C.
$6400$
Volume of the wall $=$ length $×$ breadth $×$ height
$= (8 × 100) × (6 × 100) × 22.5 ...(1m = 100\ cm)$
$=800\times600\times\frac{225}{10}$
$=800\times60\times225$
Volume of $1$ brick $=$ length $×$ breadth $×$ height
$=25\times\frac{1125}{100}\times6$
$=\frac{1125}{2}\times3$
Required number of bricks $=\frac{\text{Volume}\ \text{of}\ \text{the}\ \text{wall}}{\text{Volume}\ \text{of}\ 1\ \text{brick}}$
$=\frac{800\times60\times225}{\frac{1125}{2}\times3}$
$=\frac{800\times60\times225\times2}{1125\times3}$
$=6400$
$= (8 × 100) × (6 × 100) × 22.5 ...(1m = 100\ cm)$
$=800\times600\times\frac{225}{10}$
$=800\times60\times225$
Volume of $1$ brick $=$ length $×$ breadth $×$ height
$=25\times\frac{1125}{100}\times6$
$=\frac{1125}{2}\times3$
Required number of bricks $=\frac{\text{Volume}\ \text{of}\ \text{the}\ \text{wall}}{\text{Volume}\ \text{of}\ 1\ \text{brick}}$
$=\frac{800\times60\times225}{\frac{1125}{2}\times3}$
$=\frac{800\times60\times225\times2}{1125\times3}$
$=6400$
Need a full question paper?
Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.
Explore more
Similar questions
Write the correct answer in the following: In Fig. $\angle\text{AOB}=90^\circ$ and $\angle\text{ABC}=30^\circ,$ then $\angle\text{CAO}$ is equal to:
→The product of difference of semi-perimeter and respective sides of $\triangle\text{ABC}$ are given as $13200\ m^3$. The area of $\triangle\text{ABC},$ if its semi-perimeter is $132\ m,$ is given by:
→In fig $D$ is mid-point of $AB$ and $\text{DE || BC}$ then $AE$ is equal to:
→The volume of a sphere of radius $2r$ is:
→The lengths of the diagonals of a rhombus are $16\ cm$ and $12\ cm$. The length of each side of the rhombus is:
→Which of the following is a rational number$?$
→Which of the following is irrational?
Maximum numbers of points that can lie on a line are:
Two steel sheets each of length $a_1$ and breadth $a_2$ are used to prepare the surfaces of two right circular cylinders - one having volume $\mathrm{v}_1$ and height $\mathrm{a}_2$ and other having volume $\mathrm{v}_2$ and height $\mathrm{a}_1$. Then:
→When the polynomial $p(x)=a x^2+b x+c$ is divided by $x, x-2$ and $x+3$, the remainders obtained are 7,9 and 49 respectively. The value of $3 a+5 b+2 c$ is
→