Question
How many bricks will be required to construct a wall $8m$ long, $6\ m$ high and $22.5\ cm$ thick if each brick measures $(25cm \times 11.25cm \times 6cm)?$
✓
Answer
Length of the wall $=8 m=800 cm$
Breadth of the wall $=22.5 cm$
Height of the wall $=6 m=600 cm$
i.e., volume of wall $=800 \times 22.5 \times 600 cm^3=10800000 cm^3$
Length of the brick $=25 cm$ Breadth of the brick $=11.25 cm$
Height of the brick $=6 cm$
i.e., volume of one brick $=25 \times 11.25 \times 6=1687.5 cm^3$
$\therefore$ Number of bricks $=\frac{\text{Volume}\ \text{of}\ \text{the}\ \text{wall}}{\text{Volume}\ \text{of}\ \text{the}\ \text{brick}}$
$=\frac{10800000}{1687.5}=6400$
Breadth of the wall $=22.5 cm$
Height of the wall $=6 m=600 cm$
i.e., volume of wall $=800 \times 22.5 \times 600 cm^3=10800000 cm^3$
Length of the brick $=25 cm$ Breadth of the brick $=11.25 cm$
Height of the brick $=6 cm$
i.e., volume of one brick $=25 \times 11.25 \times 6=1687.5 cm^3$
$\therefore$ Number of bricks $=\frac{\text{Volume}\ \text{of}\ \text{the}\ \text{wall}}{\text{Volume}\ \text{of}\ \text{the}\ \text{brick}}$
$=\frac{10800000}{1687.5}=6400$
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