Question
How many electrons are present in 16 g of $\mathrm{CH}_4$ ?

Answer

1 molecule of $\mathrm{CH}_4=6+4=10$ electrons
$\Rightarrow 16 \mathrm{~g}$ of $\mathrm{CH}_4$ contains $10 \times 6.022 \times 10^{23}$ electrons
$\Rightarrow 6.022 \times 10^{24}$ electrons.

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