MCQ
How many electrons can be accommodated in a sub-shell for which $n = 3,\,l = 1$
- A$8$
- ✓$6$
- C$18$
- D$32$
Azimuthal quantum number is $I = 1 - P$ subshell
$P$ subshell has $3$ orbitals. each can hold two electrons.
So, Number of orbitals present can be calculated by the formula $(2 l+1)$
Here value of $I =1,$
Hence Number of orbitals $=2 \times 1+1=3$
$3 p \rightarrow$
$\uparrow \downarrow \uparrow \downarrow \uparrow \downarrow$
The $p$ subshell has maximum of $3$ orbitals Hence total of $6\, electrons$ can fit for $n=3$ and $l=1$
Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.
$\begin{array}{*{20}{c}}
{OH\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,O} \\
{\,|\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,||} \\
{{C_6}{H_5} - CH - C{H_2} - C - C{H_3}}
\end{array}\mathop {\xrightarrow{{(i)\,NaOBr}}}\limits_{(ii)\,{H_2}O/{H^ + }\,(iii)\,\Delta } $ product
product will be :
$E_{F{e^{2 + }}/Fe}^o\, = \, - \,0.44\,\,V\,;\,\,E_{Z{n^{2 + }}/Zn}^o\, = \, - \,0.76\,\,V\,;\,$
$E_{C{u^{ + 2}}/Cu}^o\, = \,0.34\,\,V$
Based on this data, which of the following is the strongest reducing agent ?