MCQ
How many electrons can be accommodated in a sub-shell for which $n = 3,\,l = 1$
- A$8$
- ✓$6$
- C$18$
- D$32$
Azimuthal quantum number is $I = 1 - P$ subshell
$P$ subshell has $3$ orbitals. each can hold two electrons.
So, Number of orbitals present can be calculated by the formula $(2 l+1)$
Here value of $I =1,$
Hence Number of orbitals $=2 \times 1+1=3$
$3 p \rightarrow$
$\uparrow \downarrow \uparrow \downarrow \uparrow \downarrow$
The $p$ subshell has maximum of $3$ orbitals Hence total of $6\, electrons$ can fit for $n=3$ and $l=1$
Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.
Given that $\left.\frac{2.303 \mathrm{RT}}{\mathrm{F}}=0.059 \mathrm{V} \text { at } \mathrm{T}=298 \mathrm{K}\right]$