MCQ
How many $H^+$ ions are present in $2\, mL$ of a solution whose $pH$ is $13$ ?
- A${10^{ - 16}}$
- ✓$12.04 \times {10^7}$
- C$6.02 \times {10^7}$
- D$12.04 \times {10^{13}}$
✓
Answer
Correct option: B.
$12.04 \times {10^7}$
b
$pH=13 \quad[H^+]=10^{-13} \,M$
$pH=13 \quad[H^+]=10^{-13} \,M$
Moles $=$ Molarity $\times V$ inlitre
$=\quad 10^{-13} \times \frac{2}{1000}$
$=\quad 10-13 \times 2 \times 10^{-3}$
$=\quad 2 \times 10^{-16}$
no. of $H^+$ ions $=2 \times 10^{-16} \times 6.023 \times 10^{23}$
$=12.046 \times 10^7$
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