MCQ
How many ions are produced from the complex $\ce{Co(NH_3)_6Cl_2}$ in solution?
- A$6$
- B$4$
- C$3$
- ✓$2$
✓
Answer
Correct option: D.
$2$
The given complex can be written as $\ce{Co(NH_3)_6 Cl_2}.$
Thus, $\ce{[Co(NH_3)_6]^+}$ along with two $Cl^-$ ions are produced.
Thus, $\ce{[Co(NH_3)_6]^+}$ along with two $Cl^-$ ions are produced.
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