MCQ
How many ions are produced from the complex Co(NH3)6Cl2 in solution?
- A6
- B4
- C3
- D2
3
The given complex can be written as Co(NH3)6 Cl2.
Thus, [Co(NH3)6]+ along with two Cl- ions are produced.
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$M{n_{(S)}}|Mn_{(aq)}^{ + 2}(0.4\,M)||Sn_{(aq)}^{ + 2}(0.04\,M)|S{n_{(S)}}$,
Calculate free energy change $(\Delta G)$ at $298\,K$ .
Given :$E_{M{n^{ + 2}}|Mn}^o = \, - \,1.18\,V\,;\,E_{S{n^{ + 2}}|Sn}^o\, = \, - \,0.14\,volt$
$\frac{{2.303\,RT}}{F} = 0.06$

