How many moles of $CO _2$ are obtained from complete combustion of 21 gm propene?
✓
Answer
$C _3 H _8+4.5 O _2 \longrightarrow 3 CO _2+3 H _2 O$ $\text { Moles of propene }=\frac{\text { Given mass }(g)}{\text { Molecular mass }}$ Molecular mass of propene $\left( C _3 H _8\right)=42$ $\text { Moler of propene }=\frac{21}{42}=0.5$ According to balanced equation, 1 mole of propene give 3 mole of $CO _2$ on combustion. Hence 1.5 mole $CO _2$ will form from combustion of 0.5 mole propene.
Need a full question paper?
Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.