Question
How many numbers of two digit are divisible by 3?

Answer

The first two digit number divisible by 3 is 12. and last two digit number divisible by 3 is 99. So, the required series is 12, 15, 18, ...99. Let there be n terms then $n^{th}$ term = 99 $\Rightarrow99=\text{a}+(\text{n}-1)\text{d}$ $\Rightarrow99=12+(\text{n}-1)3$ $\Rightarrow\text{n}=30$ 30 two digit number are divisible by 3.

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