Question
How many numbers of two digit are divisible by 3?
✓
Answer
The first two digit number divisible by 3 is 12.
and last two digit number divisible by 3 is 99.
So, the required series is 12, 15, 18, ...99.
Let there be n terms then nth term = 99
$\Rightarrow99=\text{a}+(\text{n}-1)\text{d}$
$\Rightarrow99=12+(\text{n}-1)3$
$\Rightarrow\text{n}=30$
30 two digit number are divisible by 3.
and last two digit number divisible by 3 is 99.
So, the required series is 12, 15, 18, ...99.
Let there be n terms then nth term = 99
$\Rightarrow99=\text{a}+(\text{n}-1)\text{d}$
$\Rightarrow99=12+(\text{n}-1)3$
$\Rightarrow\text{n}=30$
30 two digit number are divisible by 3.
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