How many numbers of two digit are divisible by 3? - Vidyadip

Question

How many numbers of two digit are divisible by $3?$

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Answer

The first two digit number divisible by $3$ is $12.$
and last two digit number divisible by $3$ is $99.$
So, the required series is $12, 15, 18, ...99.$
Let there be $n$ terms then $n^{th}$ term $= 99$
$\Rightarrow99=\text{a}+(\text{n}-1)\text{d}$
$\Rightarrow99=12+(\text{n}-1)3$
$\Rightarrow\text{n}=30$
30 two digit number are divisible by $3.$

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