MCQ
How many primary amines are possible for the formula ${C_4}{H_{11}}N$
- A$1$
- B$2$
- C$3$
- ✓$4$
✓
Answer
Correct option: D.
$4$
d
(d) $\mathop {C{H_3} - C{H_2} - C{H_2} - C{H_2} - N{H_2}}\limits_{{\text{(1 - aminobutane)}}} $
$\mathop {C{H_3} - C{H_2} - \mathop {\mathop {CH\,\,\,}\limits_{|\,\,\,\,\,\,\,\,\,\,\,} }\limits_{N{H_2}} - C{H_3}}\limits_{{\text{(2 - aminobutane)}}} $
$\mathop {C{H_3} - \mathop {\mathop {C\,\, - \,}\limits_{|\,\,\,\,\,\,\,\,}^{|\,\,\,\,\,\,\,\,} }\limits_{N{H_2}}^{C{H_3}} C{H_3}}\limits_{{\text{(2 - Methyl - 2 - aminopropane)}}} $
$\mathop {\mathop {C{H_3}}\limits^{3\,\,\,\,\,\,\,\,\,} - \mathop {CH\,\,\,}\limits_{\mathop {|\,\,\,\,\,\,\,\,\,\,}\limits_{C{H_3}} }^{2\,\,\,\,\,} - \mathop {C{H_2}}\limits^{1\,\,\,\,\,\,\,\,} - N{H_2}}\limits_{{\text{(2 - Methyl - 1 - aminopropane)}}} $
(d) $\mathop {C{H_3} - C{H_2} - C{H_2} - C{H_2} - N{H_2}}\limits_{{\text{(1 - aminobutane)}}} $
$\mathop {C{H_3} - C{H_2} - \mathop {\mathop {CH\,\,\,}\limits_{|\,\,\,\,\,\,\,\,\,\,\,} }\limits_{N{H_2}} - C{H_3}}\limits_{{\text{(2 - aminobutane)}}} $
$\mathop {C{H_3} - \mathop {\mathop {C\,\, - \,}\limits_{|\,\,\,\,\,\,\,\,}^{|\,\,\,\,\,\,\,\,} }\limits_{N{H_2}}^{C{H_3}} C{H_3}}\limits_{{\text{(2 - Methyl - 2 - aminopropane)}}} $
$\mathop {\mathop {C{H_3}}\limits^{3\,\,\,\,\,\,\,\,\,} - \mathop {CH\,\,\,}\limits_{\mathop {|\,\,\,\,\,\,\,\,\,\,}\limits_{C{H_3}} }^{2\,\,\,\,\,} - \mathop {C{H_2}}\limits^{1\,\,\,\,\,\,\,\,} - N{H_2}}\limits_{{\text{(2 - Methyl - 1 - aminopropane)}}} $
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