Question
How many products will be formed in above reaction ?



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(Given : $h =6.63 \times 10^{-34} \,Js , N _{ A }=6.02 \times 10^{23} \,mol ^{-1}$, $c =3 \times 10^{8}\, ms ^{-1}$ )
$SO _{2} Cl _{2}+2 H _{2} O \rightarrow H _{2} SO _{4}+2 HCl$ $16\,moles$ of $NaOH$ is required for the complete neutralisation of the resultant acidic mixture. The number of moles of $SO _{2} Cl _{2}$ used is.