MCQ
How many protons are present in $1.8\,g \,NH_4^+$ ............. $N_A$
- A$1$
- B$1.2$
- ✓$1.1$
- D$11$
✓
Answer
Correct option: C.
$1.1$
c
No. of protons in one $\mathrm{NH}_{4}^{+}$ ion $=7+4=11$
No. of protons in one $\mathrm{NH}_{4}^{+}$ ion $=7+4=11$
No. of $\mathrm{NH}_{4}^{+}$ ions in $1.8\, \mathrm{g}=\frac{1.8}{18} \times \mathrm{N}_{\mathrm{A}}=0.1\, \mathrm{N}_{\mathrm{A}}$
$\text { No. of protons in } 1.8\, \mathrm{g} \,\mathrm{NH}_{4}^{+} =11 \times 0.1\, \mathrm{N}_{\mathrm{A}}$
$=1.1 \,\mathrm{N}_{\mathrm{A}}$
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