$CH_3CH=CHCH_2CHBrCH_3$
- A$8$
- B$2$
- ✓$4$
- D$6$
$CH_3CH=CHCH_2CHBrCH_3$
Number of optical isomers $=2^{n}$
where, $n=$ number of asymmetric carbon atoms
$2^{1}=2$
Number of geometrical isomers $=2^{n}$ where, $n=$ number of double bonds $=2^{1}=2$
Hence, total number of stereoisomers $=$ Total optical isomers $4\,-$ Total geometrical isomers
$=2+2=4$
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$\begin{matrix}
\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,C{{H}_{3}}\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,O \\
\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,|\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,|| \\
HOC{{H}_{2}}C{{H}_{2}}CHC{{H}_{2}}C{{H}_{2}}COH \\
\end{matrix}$ $\xrightarrow[tetrahydro\,\,futan ]{(x)\,\,C{{H}_{3}}Li}$ $\xrightarrow[{{H}_{2}}]{N{{H}_{4}}Cl}$ $\underset{Compound\,\,\,A\,\,63\,\%}{\mathop{\begin{matrix}
\,\,\,\,\,\,\,\,\,\,\,\,C{{H}_{3}}\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,O\, \\
\,\,\,\,\,\,\,\,\,\,\,\,|\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,|| \\
HOC{{H}_{2}}C{{H}_{2}}CHC{{H}_{2}}C{{H}_{2}}-C-C{{H}_{3}} \\
\end{matrix}}}\,$ $\underset{37\,\%}{\mathop{+\,\,Compound\,\,(B)}}\,$
Value of $(x)$ in above reaction is
