$CH_3CH=CHCH_2CHBrCH_3$
$CH_3CH=CHCH_2CHBrCH_3$
Number of optical isomers $=2^{n}$
where, $n=$ number of asymmetric carbon atoms
$2^{1}=2$
Number of geometrical isomers $=2^{n}$ where, $n=$ number of double bonds $=2^{1}=2$
Hence, total number of stereoisomers $=$ Total optical isomers $4\,-$ Total geometrical isomers
$=2+2=4$
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$Time (sec)$ Rate $(mol\, L^{-1} sec.^{-1})$
$0$ $1.60 \times 10^{-2}$
$10$ $1.60 \times 10^{-2}$
$20$ $1.60 \times 10^{-2}$
$30$ $1.60 \times 10^{-2}$
From the above data, the order of reaction is

$Pt ( s )\left| H _2( s )( latm )\right| H ^{+}\left( aq ,\left[ H ^{+}\right]=1\right)|| Fe ^{3+}( aq ), Fe ^{2+}( aq ) \mid \operatorname{Pt}( s )$
Given : $E _{ Fe ^{3+} / e ^{2 *}}^0=0.771\,V$ and $E _{ H ^{+}+\frac{1}{2} H _2}^0=0 V , T =298\,K$
If the potential of the cell is $0.712\,V$ the ratio of concentration of $Fe ^{2+}$ to $Fe ^{2+}$ is $........$.(Nearest integer)