Question
How many terms are there in the A.P.?
$7, 10, 13, ..... 43.$
$7, 10, 13, ..... 43.$
✓
Answer
$7,10,13, \ldots . . ., 73 .$
From given A.P.
$a=7, d=10-7=3, a_n=a+(n-1) d$
Let $a_n=43$ (last term)
$7+(n-1) 3=43$
$(n-1)=\frac{36}{3}=12$
$n=13$
$\therefore 13$ terms are there in given A.P.
From given A.P.
$a=7, d=10-7=3, a_n=a+(n-1) d$
Let $a_n=43$ (last term)
$7+(n-1) 3=43$
$(n-1)=\frac{36}{3}=12$
$n=13$
$\therefore 13$ terms are there in given A.P.
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