Question
How many three-digit numbers are divisible by $9$?

Answer

The two-digit numbers divisible by $9$ start from
$108, 117, 126, 135, ..., 999$
Here,
$a = 108$
$d = 9$
$a_n = a + (n - 1)d$
$\Rightarrow 999 = 108 + (n - 1)(9)$
$\Rightarrow 999 = 108 + 9n - 9$
$\Rightarrow 900 = 9n$
$\Rightarrow n = 100$
This, $100$ two-digit number are divisible by $9$.

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