MCQ
How many unpaired electrons are there in $N{i^{2 + }}$
- ✓$2$
- B$4$
- C$5$
- D$0$
✓
Answer
Correct option: A.
$2$
a
(a)$Ni \to 1{s^2}2{s^2}2{p^6}3{s^2}3{p^6}3{d^8}4{s^2}$
(a)$Ni \to 1{s^2}2{s^2}2{p^6}3{s^2}3{p^6}3{d^8}4{s^2}$
$N{i^{2 + }} \to 1{s^2}2{s^2}2{p^6}3{s^2}3{p^6}3{d^8}$
$3{d^8} = 10 - 2 = 2$ unpaired electron.
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