Question
How much copper can be obtained from 100 g of copper sulphate $\left(\mathrm{CuSO}_4\right)$ ?

Answer

$\text { Molar mass of } \mathrm{CuSO}_4=63.54+32.06+(4 \times 16)=159.6 \mathrm{~g} \mathrm{~mol}^{-1}$
$159.6 \mathrm{g} \mathrm{~CuSO}_4 \text { contains }=63.54 \mathrm{~g} \mathrm{Cu}$
$1 \mathrm{g} \mathrm{~CuSO}_4 \text { contains }=\frac{63.54}{159.6} \mathrm{~g} \mathrm{Cu}$
$\therefore 100 \mathrm{g} \mathrm{~CuSO}_4 \text { contains }=\frac{63.54 \times 100}{159.6}$
$=39.81 \mathrm{g} \mathrm{~Cu}$

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